Question

How do you divide `(2-7i)/(2-8i)` in trigonometric form?

Answer 1

Find the polar form `C_p = (R, theta)`
given `C = x +iy`
Then the polar form is `R = sqrt(x^2+y^2)`
And `theta= tan^-1 (y/x)`

Thus `R_1= sqrt(53); theta_1= tan^-1(7/2);`

careful on the angle use the sign of the imaginary number to get it right (hint it is in the 4th quadrant...

`R_2= sqrt(68); theta_2 = tan^-1(8/2);`

again make sure you have the right angle.

now divide `R = R_1/R_2` and the angle is simply the difference of `theta = theta_1 - theta_2`

Good luck, hope it helped
Yonas