How do you simplify #sin(x+y)+tan(x-y)/cos(x+y)# to trigonometric functions of x and y?
1 Answer
Jan 20, 2016
Explanation:
Use the following identities:
#sin(x+y)=sinxcosy+cosxsiny# #cos(x+y)=cosxcosy-sinxsiny# #tan(x-y)=(tanx-tany)/(1+tanxtany)#
This gives us the expression
#sinxcosy+cosxsiny+((tanx-tany)/(1+tanxtany))/(cosxcosy-sinxsiny)#
