What is the standard form of #y=(x^3 - 8)(x-2) #?
1 Answer
Jan 20, 2016
# x^4 - 2x^3 - 8x + 16 #
Explanation:
multiply out the brackets ( distributive law ) and 'collect like terms '
# x^3(x - 2 ) - 8 (x - 2 ) #
# = x^4 -2 x^3 - 8x + 16 #
