What is the standard form of #y= (-2x^2-2)(4x-1) #?
1 Answer
Jan 21, 2016
#- 8x^3 + 2x^2 - 8x + 2 #
Explanation:
Multiply out brackets (distributive law ) and collect ' like terms'.
# -2x^2 (4x - 1 ) - 2 (4x - 1 ) = -8x^3 + 2x^2 - 8x + 2 #
# = - 8x^3 + 2x^2 - 8x + 2 #
