How do you find the derivative of the function: #(arctan(6x^2 +5))^2#?
1 Answer
Jan 23, 2016
Explanation:
This will require a little chain rule.
The first issue is the second power, which can be dealt with as such:
#f'(x)=2arctan(6x^2+5)d/dx[arctan(6x^2+5)]#
Now, we must deal with the
#f'(x)=2arctan(6x^2+5)*(d/dx[6x^2+5])/((6x^2+5)^2+1)#
Simplify:
#f'(x)=(2arctan(6x^2+5)*12x)/((6x^2+5)^2+1)#
#f'(x)=(24xarctan(6x^2+5))/((6x^2+5)^2+1)#