What is the area of a triangle with sides of length 1, 2, and 2?

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Answer 1 · 2016-01-25T08:52:23

#Area=sqrt15/4# square units

Use the Heron's formula

#Area=sqrt(s*(s-a)(s-b)(s-c)#

Let #a=2, b=2, c=1#

compute #s#

#s=1/2(a+b+c)=1/2*(2+2+1)=5/2#

Now, compute the Area

#Area=sqrt(s*(s-a)(s-b)(s-c)#

#Area=sqrt(5/2*(5/2-2)(5/2-2)(5/2-1)#

#Area=sqrt(5/2*(1/2)(1/2)(3/2))=sqrt(15/16)=sqrt15/4#