Question

Question #9acfd

Answer 1

For `7+` to be equal to `2+` we need to add `5-` which means adding five electrons `5e^-`.

Explanation:

This is the reduction half-equation in a redox reaction involving the oxidizing agent `KMnO_4`.

The equation is then:

`MnO_4^(-)(aq)+8H^(+)(aq)+ 5e^(-) -> Mn^(2+)(aq) + 4H_2O(l)`

The 5 electrons here are added to balance the charges to be equal to the left and right sides.

To the left side we have:

`1- " from " MnO_4^(-) " and "8+ " from " H^+=7+`

To the right side we have:

`2+ " from " Mn^(2+) " and "0 " from " H_2O=2+`

For `7+` to be equal to `2+` we need to add `5-` which means adding five electrons `5e^-`.

Here is a video that explains the balancing of a redox reaction in acidic medium.

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Balancing Redox Reactions | Acidic Medium.