Question

What is the logarithmic concentration of the hydroxide ion in aqueous solution?

Answer 1

I presume you mean `pOH`?

Explanation:

We would calculate `pOH` the same way we calculate `pH`. That is `pOH` `=` `-log_(10)[OH^-]`, where `[OH^-]` is the concentration of hydroxide ion.

Given that `10^-14` `=` `[H_3O^+][OH^-]`,

then `log_(10)10^(-14)` `=` `log_(10)[H_3O^+]` `+` `log_(10)[HO^-]`

And thus `14` `=` `pH + pOH` (because by definition `log_(10)10^(-14)` `=` `-14`.

So you need to find hydroxide (or acid) concentration, and take its negative logarithm to the base 10.