What is the equation of the circle with a center at (4,−3) and a radius of 5?
1 Answer
Jan 26, 2016
(x−4)2+(y+3)2=25
Explanation:
The standard form of a circle with a center at
(x−h)2+(y−k)2=r2
Since the center is
⎧⎪⎨⎪⎩h=4k=−3r=5
Thus, the equation of the circle is
(x−4)2+(y−(−3))2=52
This simplifies to be
(x−4)2+(y+3)2=25