What is the equation of the circle with a center at (4,3) and a radius of 5?

1 Answer
Jan 26, 2016

(x4)2+(y+3)2=25

Explanation:

The standard form of a circle with a center at (h,k) and a radius r is

(xh)2+(yk)2=r2

Since the center is (4,3) and the radius is 5, we know that

h=4k=3r=5

Thus, the equation of the circle is

(x4)2+(y(3))2=52

This simplifies to be

(x4)2+(y+3)2=25