What is the equation of the circle with a center at #(4 ,-3 )# and a radius of #5 #?
1 Answer
Jan 26, 2016
#(x-4)^2+(y+3)^2=25#
Explanation:
The standard form of a circle with a center at
#(x-h)^2+(y-k)^2=r^2#
Since the center is
#{(h=4),(k=-3),(r=5):}#
Thus, the equation of the circle is
#(x-4)^2+(y-(-3))^2=5^2#
This simplifies to be
#(x-4)^2+(y+3)^2=25#