Question

How do you solve `x^2 + 2x + 1 = 0`?

Answer 1

See explanation.

Explanation:

`x^2 + 2x + 1 = (x+1)^2`

This represents the equation for a right way up parabola touching the `x`-axis at `x=-1`. The `y`-intercept is `+1`

graph{x^2 + 2x + 1 [-10, 10, -5, 5]}