What is the cross product of #[-1, 2, 2]# and #[4,3,6] #?

1 Answer
Bio
Jan 27, 2016

#[6,14,-11]#

Explanation:

Since cross product is distributive, you can "expand" it

#(-hati + 2hatj + 2hatk) xx (4hati + 3hatj + 6hatk) #

#= (-hati)xx(4hati) + (-hati)xx(3hatj) + (-hati)xx(6hatk)#
#+ (2hatj)xx(4hati) + (2hatj)xx(3hatj) + (2hatj)xx(6hatk)#
#+ (2hatk)xx(4hati) + (2hatk)xx(3hatj) + (2hatk)xx(6hatk)#

#= 0 - 3hatk + 6hatj#
#- 8hatk + 0 + 12hati#
#+ 8hatj - 6hati + 0#

#= 6hati + 14hatj - 11hatk #

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