How do you simplify #sqrt36/sqrt3#?

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Answer 1 · 2016-01-28T16:23:05

#=2sqrt3#

#sqrt36/sqrt3#

We know that #sqrt36= 6#

So,
#sqrt36/sqrt3 = color(blue)(6)/sqrt3#

Now we rationalise the denominator:
#(6)/sqrt3 =((6) xx sqrt3) /(sqrt3 xx sqrt3 #

#=(6sqrt3)/(sqrt3 xx sqrt3#

#=(6sqrt3)/ 3#

#=(cancel6sqrt3)/ cancel3#

#=2sqrt3#