How do you solve the following system of equations?: #x+y= -2 , x - y= 10#?

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Answer 1 · 2016-01-28T23:36:32

#x=4#
#y=-6#

#x= -2-y#

subsitute #x=-2-y# into #x-y=10#

#rarr-2-y-y=10#

#rarr-2-2y=10#

#rarr-2y=12#

#y=-6#

substitute #y=-6# into #x-y=10#

#rarrx-6-(-6)=10#

#rarrx+6=10#

#x=4#

This is just substitution, you can also use elimination

#rarrx+y=-2#

#rarrx-y=10#

add the two equations
(the y's cancel each other out)

#rarr2x= 8#

#x=4#

substitute #x=4# into #x-y=10#

#rarr4-y=10#

#rarr-y=6#

#y=-6#