Question

How can you use trigonometric functions to simplify `16 e^( ( 5 pi)/6 i )` into a non-exponential complex number?

Answer 1

`16 [ cos((5pi)/6) + isin((5pi)/6 ) ]`

Explanation:

Euler's theorem states : `e^(itheta) = costheta + isintheta`

Here `theta =( 5pi)/6`

hence `16e^((5pi)/6 i = 16 [ cos((5pi)/6) + isin((5pi)/6) ]`