Question

If a current of `2 A` passing through a circuit generates `15 W` of power, what is the resistance of the circuit?

Answer 1

Assuming that the resistors are connected in series, the effective resistance is `3.75 Omega`.

Explanation:

`P = VI`

Since by Ohm's Law, `V=IR`,
`P = I^2R`.

`15W=(2"A")^2R_{"eff"}`

`R_{"eff"} = 15/4 Omega`