How do you solve the triangle when a=7, b=9, A=34?

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Answer 1 · 2016-01-31T05:22:31

B = 45.96 , C = 100.03 , c = 12.326

Use sin rule of triangles

If a, b, c are sides of a triangle and angles opposite to them are A, B, C respectively then

#(sin(A))/a=(sin(B))/b=(sin(C))/c=k# (any constant)

Using this we get

#(sin(34))/7=(sin(B))/9#

B = 45.96

Now #C=180-(A+B)#

C = 100.03

Now using

#(sin(B))/b=(sin(C))/c#

c = 12.326