Question

What is the center and radius of the circle with equation `x^2 + (y + 6)^2 = 49`?

Answer 1

The center is `(0, -6)` and the radius is `7`.

Explanation:

The equation of a circle with center `(a, b)` and radius `r` in standard form is `(x-a)^2+(y-b)^2=r^2`.

In this case, `a=0`, `b=-6` and `r=7` `(sqrt49)`.