What is #(-3x^2-11x + 13)-(18x^2 +19x-8)#?

Question

1428 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2016-02-01T05:01:31

#-21x^2-30x+21#

This can be written as #-3x^2-11x+13 +[ (-1)xx(18x^2+19x-8)]#
#-3x^2-11x+13+(-18x^2-19x+8)#
#(-3-18)x^2+(-11-19)x+(13+8)#
#-21x^2-30x+21#

Answer 2 · 2016-02-01T13:13:50

#(-3x^2-11x+13)-(18x^2+19x-8)#

Always remember that you must multiply your signs and write when subtracting:

#rarr=(-3x^2-11x+13)-18x^2-19x+8#

Remove brackets:

#rarr-3x^2-11x+13-18x^2-19x+8#

#rarr-21x^2-11x+13-19x+8#

#rarr-21x^2-30x+13+8#

#rarr=-21x^2-30x+21# (Final answer)