How do you solve for #y# in the equation #3xy + 9y + 14#?

1 Answer
Daksh S.
Feb 1, 2016

Sorry, this is not an equation. Assuming it to be equal to c (any constant), ans is

Explanation:

#3xy+9y+14 = c#
#y(3x+9)+14 = c#
#y(3x+9) = c-14#
#y = (c-14)/(3x+9)#

Now put the value of c as per your wish.

P.S. At #x = 3#, the value of y will not be defined.

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