Question

How do you find the equation of the circle passing through the point (2,6), with center (3,-5)?

Answer 1

equired equation would be `(x-3)^2 +(y+5)^2 = 122`

Explanation:

Here , it is needed to find the radius of the circle. It would be `sqrt((2-3)^2 +(6+5)^2)= sqrt122`

Required equation would be `(x-3)^2 +(y+5)^2 = 122`