Question

How do you find the inverse of `y = -log_4x`?

Answer 1

`f^-1(x)=4^-x`

Explanation:

Given that `y=-log_4x`. It can also be written as `f(x)=-log_4x`
This means that `f(x)=y\impliesf^-1(y)=x`

Now, I believe you're accustomed to the realm of logarithms so that you know `y=-log_4x\implies-y=log_4x\implies4^-y=x`
We've written above that `f^-1(y)=x` so that just means `f^-1(y)=4^-y`.
Replacing the `y` parameter by the `x` parameter is just what you'll find to be the answer.