Question

How do you divide `(5-12i)/(6+2i)` in trigonometric form?

Answer 1

`3/20-(41i)/20`

Explanation:

Multiply the expression with the cojugate of 6+2i, both in the numerator and the denominator. Thus it is,

`(5-12i)/ (6+2i) * (6-2i)/(6-2i)` = `(6-82i)/40` = `3/20-(41i)/20`