What is the standard form of # y=(11x - x^2)(11 - x) #?

1 Answer
Feb 3, 2016

#x^3-22x^2+121x#

Explanation:

The way we solve this equation is by using the distributive property. Here is an example of how it works:
i.stack.imgur.com

In this case, we multiply #(11x*11)+(11x*-x)+(-x^2*-11)+(-x^2*-x)#.
This becomes #121x+(-11x^2)+(-11x^2)+x^3#, which we can simplify to #121x-22x^2+x^3#.

Standard form is #ax^3+bx^2+cx+d#, so lets try to rewrite our expression in this form.
It gos from highest degree to lowest, so let's right it like that. #x^3-22x^2+121x+0#. We can ignore the zero, so we don't need to add it if we don't want to.

The final form is #x^3-22x^2+121x#