How do solve the following linear system?: # x+2y=1 , 6x=29-8y #?

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Answer 1 · 2016-02-03T11:24:25

#x=25/2# #y=-23/4#

suppose,
#x+2y=1.......................................................(i)#
#6x=29-8y..................................................(ii)#

from #(ii)# we can find,

#6x+8y=29..................................................(iii)#

now,
#6xx(i)-(iii)=>#
#cancel(6x)+12y=6#
#cancel(6x)+8y=29#
...............................
#=>4y=-23#
#=>y=-23/4#

now, putting #y=-23/4# in #(iii)# we get,

#6x-46=29#

#=>6x=75#

#=>x=25/2#