Question

A jogger runs in a straight line with an average speed of 5 m/s for 4 minutes, then finishes with an average speed of 4 m/s for 3 minutes. What is his total displacement?

Answer 1

You only need `v=(\Delta x)/(\Delta t)`

Explanation:

By using `v=(\Delta x)/(\Delta t)` and isolating `\Delta x=v \cdot \Delta t` you don't need anything else

As it is an straight line, no tricks involved at an average speed of 4m/s for 3minutes=180secons notice the change in the units of time ( either your speed is in m/min or your time in mins, you can't just combine m/s with mins)

`\Delta x=4m/s \cdot 180s=720m/s`