Question

What is the standard form of `y=(3x-5)(6x-2)`?

Answer 1

`y = 18x^2 - 36x + 10`

Explanation:

The standard form of an equation is:
`y = ax^2 - bx + c`

So, you have to develop the right member which is the form :
`(a + b) (c + d)`
We develop as :
`(a*c) + (a*d) + (b*c) + (b*d)`

So :
`y = (3x - 5)(6x-2)`
`y = (3x * 6x) + (3x * -2) + (- 5 * 6x) + (-5 * -2)`
`y = 18x^2 - 6x -30x + 10`
`y = 18x^2 - 36x + 10`