A block of silver has a length of 0.93 m, a width of 60 mm and a height of 12 cm. How do you find the total resistance of the block if it is placed in a circuit such that the current runs along its length? Along its height? Along its width?

1 Answer
Feb 4, 2016

for alongside length:
R_l=0,73935*10^(-8) Omega
for alongside width:
R_w=0,012243*10^(-8) Omega
for alongside height:
R_h=2,9574*10^(-8) Omega

Explanation:

"formula required:"
R= rho *l/s
rho=1,59*10^-8
R= rho *(0,93)/(0,12*0,06)= rho*0,465
"for alongside length"
R=1,59*10^-8*0,465=0,73935*10^(-8) Omega

R= rho *(0,06)/(0,93*0,12)= rho*0,0077
"for alongside width"
R= 1,59*10^(-8)*0,0077=0,012243*10^(-8) Omega

R= rho *(0,12)/(0,06*0,93)= rho*1,86
" for alongside height"
R=1,59*10^(-8)*1,86=2,9574*10^(-8) Omega