Two charges of -1 C and 5 C are at points (1,-5,3 ) and ( -3 , 9, 1 ), respectively. Assuming that both coordinates are in meters, what is the force between the two points?

1 Answer
Feb 4, 2016

F=-2,12264*10^8N

Explanation:

Delta x=-3-1=-4
Delta y=9-(-5)=14
Delta z=1-1=0
r=sqrt Delta x^2+ Delta y^2 +Delta z^2
r=sqrt 16+196+0
"distance between two charges is:"
r=sqrt 212
r^2= 212
F=k*(q_1*q_2)/r^2
F=9*10^9(-1*5)/212
F=(-45*10^9)/212
F=-2,12264*10^8N