How do you simplify #(5+4i)(5+4i)#?
1 Answer
Feb 5, 2016
9 + 40i
Explanation:
distribute the brackets using FOIL
(5+4i)(5+4i) =
# 25 +20i+20i+16i^2 # [remember that
# i^2 =(sqrt(-1))^2 = -1 # ]hence
# 25+20i+20i -16 = 9 + 40i #
