How do solve the following linear system?: # y=-3x+4 , 2x+5y=1 #?

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Answer 1 · 2016-02-06T13:51:07

#x=19/13#
#y=-5/13#

start from the given then rearrange
the equations this way

#3x+y=4# first equation
#2x+5y=1# second equation

#15x+5y=20# after multiplying first equation by 5 -(third equation)

#13x+0=19# after subtracting the second from the third equation.

#13x=19# by simplification

divide by 13 now

#(13x)/13=19/13# by simplification

#(cancel13x)/cancel13=19/13# by simplification

#x=19/13#

solve #y# using first equation by substituting the x value.

#3x+y=4# first equation

use #x=19/13#

#3(19/13)+y=4#

#y=4-3(19/13)#

#y=(52-57)/13#

#y=-5/13#

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