If #f(x+3)=[x+1]/[2x-1]# then how do you find f(x-1)?

Question

1737 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2016-02-06T14:42:07

#f(x-1)=(x-3)/(2x-9)#

Solution is to find #f(x)# first.

the given is #f(x+3)=(x+1)/(2x-1)#

try to locate #(x+3)# at the right side of the equation

#f(x+3)=(x+3-3+1)/(2(x+3-3)-1)# add 3 and subtract 3 where you can find x because it is the same as adding nothing. Then simplify retaining the (x+3)

#f(x+3)=(x+3-2)/(2(x+3)-6-1)=((x+3)-2)/(2(x+3)-7)#

so that (x+3) can now be changed to simply x

#f(x)=(x-2)/(2x-7)#

use (x-1) at this point in place of x in f(x)

#f(x-1)=(x-1-2)/(2(x-1)-7)#

#f(x-1)=(x-3)/(2x-9)#

Have a nice day from the Philippines !