What is the equation of the line that has a slope of 0 and a y-intercept of -2/3?

2 Answers
Feb 8, 2016

3y+2= 0 is the equation..

Explanation:

y = mx + c is the basic equation of a straight line that has a slope of m and y-intercept is c.

here, m is 0 and c is a value of -2/3.

By putting the values in the equation, we get

y = 0.x + -(2/3)
or, y = -(2/3)
or, 3 y = - 2
or, 3 y + 2 = 0

y=-2/3 is the required horizontal line because, the slope m=0

Explanation:

Given b=-2/3 the y-intercept

also given m=0

we use y=mx+b form

y=0*x+(-2/3)

simplifies to

y=-2/3

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