What is the equation of the line that has a slope of 0 and a y-intercept of #-2/3#?

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Answer 1 · 2016-02-08T09:52:45

3y+2= 0 is the equation..

#y = #mx + c is the basic equation of a straight line that has a slope of m and y-intercept is c.

here, m is 0 and c is a value of -2/3.

By putting the values in the equation, we get

#y = 0.#x + # -(2/3)#
or, #y = -(2/3)#
or, 3 #y = # - 2
or, 3 #y +# 2 = 0

Answer 2 · 2016-02-08T09:55:20

#y=-2/3# is the required horizontal line because, the slope #m=0#

Given #b=-2/3# the y-intercept

also given #m=0#

we use #y=mx+b# form

#y=0*x+(-2/3)#

simplifies to

#y=-2/3#

have a nice day from the Philippines!