How do you solve #y = log^3(78.5)#?

1 Answer
Feb 8, 2016

#y=6.80358827392#

Explanation:

There is no way to simplify this, other than writing this as #log(78.5)# multiplied by itself #3# times.

#y=log^3(78.5)=log(78.5)xxlog(78.5)xxlog(78.5)#

Note that this is different than the other logarithm rules:

  • #log(a^b)=bxxlog(a)#

#" "#This would apply if the question were #log(78.5^3)#.

  • #log(a)+log(b)=log(ab)#

#" "#This would apply if the question were #log(78.5)+log(78.5)+log(78.5)#.

However, the only way to find this is the use a calculator:

#y=log(78.5)xxlog(78.5)xxlog(78.5)=color(blue)(6.80358827392#