How do you rationalize the denominator of #sqrt7/sqrt5#?

1 Answer
Feb 9, 2016

#(sqrt 15) / 5#

Explanation:

Observe the denominator. Here denominator is #sqrt 5#.

So multiply numerator and denominator by #sqrt 5#, which makes it

#(sqrt 7) / (sqrt 5)# * #(sqrt 5)/(sqrt 5)#

i.e. #(sqrt 15) / 5#

If denominator is of type #a+-sqrt b# type,

multiply it by #a -sqrt b#, if it is #a+sqrt b#.

And by #a+sqrt b#, if it is #a -sqrt b#.