How do solve the following linear system?: # 6 x+3y=11 , x+y=6 #?

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Answer 1 · 2016-02-10T03:34:44

#x=-7/3#, #y=25/3#

Please refer to some of my earlier replies. To solve a system of two linear equations in two variables you have to first eliminate one of variables.

The equations are #6x+3y=11# and #x+y=6#.

Multiplying latter by 3 gives us #3x+3y=18#.

Now subtracting first equation #6x+3y=11# from #3x+3y=18#
gives us #3x=-7# or #x=-7/3#

Putting #x=-7/3# in #x+y=6# gives us

#y=6-x# or #y=6-(-7/3)#, which gives us

#y=25/3#