Question

If a projectile is shot at an angle of `(pi)/8` and at a velocity of `17 m/s`, when will it reach its maximum height?

Answer 1

`t_m=0,6632 s`
`h_m=2,1564 m`

Explanation:

`alpha=pi/8*180/pi=22,5^o`
`t_m=v_i*sin alpha/g`
`t_m=17*sin (22,5)/(9,81)`
`t_m=0,6632 s" elapsed time to reach maximum height"`
`h_m=(v_i^2*sin^2 alpha)/(2*g)`
`h_m=(289*0,1464)/(19,62)`
`h_m=2,1564 m " maximum height"`