How many moles are in 3.45 * 10^243.451024 molecules of calcium iodide?

1 Answer
Feb 10, 2016

In 11 mole of CaI_2CaI2, there are 6.022xx10^236.022×1023 formula units of CaI_2CaI2.

Explanation:

So, moles of CaI_2CaI2 == (3.45xx10^24)/(6.022xx10^23*mol^-1)3.45×10246.022×1023mol1 ~= 66 "moles"moles.

How many moles of iodine atoms are in this molar quantity?