How do you solve #4x - y = 6# and #3x + y = 1#?
1 Answer
Feb 11, 2016
Explanation:
Notice that when the two equations are added to one another, the
Add the two equations:
#{:(color(white)("(")4x,-y,=6," "),("("3x,+y,=1")",+),(color(white)("(")color(blue)(7x),cancel(+0y),color(blue)(=7)," "):}#
The resulting equation
#(7x)/7=7/7" "" "=>" "" "color(red)(x=1#
This can be substituted into either equation to solve for
#3color(red)x+y=1" "" "=>" "" "3color(red)((1))+y=1#
Solve the resulting equation:
#3+y=1#
#color(green)(y=-2#