A charge of -2 C is at the origin. How much energy would be applied to or released from a 4 C charge if it is moved from (7 ,5 ) to (9 ,-2 ) ?

1 Answer
Feb 11, 2016

W=0,062 J

Explanation:

V=k*q/d" voltage of any charge on the any point "
V_A=k*q_1/sqrt 74 " potential of charge of -2C on the point(7,5)"
V_B=k*q_1/sqrt 85" potential of charge of -2C on the point(9,-2)"
V_(AB)=V_B-V_A
V_(AB)=k*q(1/sqrt 85-1/sqrt 74)
V_(AB)=k*q(sqrt 74-sqrt 85)/sqrt (74*85)
W=q*V_(AB)
"energy required for charge of 4C to move from(7,5) to (9,-2)"
W=4*k*q(sqrt 74-sqrt 85)/sqrt (74*85)
W=4*(-2)(sqrt 74-sqrt 85)/sqrt (74*85)*
W=-8*(8,602-9,219)/(79,31)
W=0,062 J