Question

What is the angular momentum of a rod with a mass of `15 kg` and length of `4 m` that is spinning around its center at `15 Hz`?

Answer 1

`P=7200*pi`

Explanation:

`P=I*omega`
`I=m*r^2`
`omega= 2*pi*f`
`P=m*r^2*2*pi*f`
`P=15*4^2*2*pi*15`
`P=15^2*4^2*2*pi`
`P=225*16*2*pi`
`P=225*32*pi`
`P=7200*pi`