Two charges of -2 C and 3 C are positioned on a line at points 5 and -6 , respectively. What is the net force on a charge of -1 C at 0 ?

1 Answer
Feb 12, 2016

F_n=3*10^7

Explanation:

F:" force between two charges"
F=k*(q_1*q_2)/r^2" Coulomb's law"
x:" distance between the charge of 3C and -1C"
x=6-0=6
y:" distance between the charge of -1C and -2C"
y:5-0=5
F_1:" Force between the charge of 3C and -1C"
F_1=k*(3*(-1))/6^2
F_1=(-3*k)/36
F_2:" Force between the charge of -1C and -2C"
F_2=(k*(-1)*(-2))/5^2
F_2=(2*k)/25
F_n=(-3*k)/36+(2*k)/25
F_n=(-75*k+72*k)/(36*25)
F_n=(-cancel(3)*k)/(cancel(36)*25)
F_n=k/(12*25)" , "k=9*10^9
F_n=(cancel(9)*10^9)/(cancel(12)*25)" ; "F_n=(3*10^9)/(4*25)
F_n=3*10^7