A charge of #24 C# passes through a circuit every #9 s#. If the circuit can generate #8 W# of power, what is the circuit's resistance?

1 Answer
Feb 12, 2016

Use: #P=I^2R#, where I is the current, and I=charge/time=24C/9s=8/3 Amps. You will find that the resistance, R = #1.125# Ohms.

Explanation:

Use: #P=I^2R#, where I is the current, and I=charge/time=24C/9s.

Now:
#R = P/I^2#
P=8 Watts

#I = (24C)/(9s) = 8/3# Amperes

#R = 8/(8/3)^2# Ohms = #(9/8)# Ohms

You will find that the resistance, R = #1.125# Ohms.