Question

A charge of `24 C` passes through a circuit every `9 s`. If the circuit can generate `8 W` of power, what is the circuit's resistance?

Answer 1

Use: `P=I^2R`, where I is the current, and I=charge/time=24C/9s=8/3 Amps. You will find that the resistance, R = `1.125` Ohms.

Explanation:

Use: `P=I^2R`, where I is the current, and I=charge/time=24C/9s.

Now:
`R = P/I^2`
P=8 Watts

`I = (24C)/(9s) = 8/3` Amperes

`R = 8/(8/3)^2` Ohms = `(9/8)` Ohms

You will find that the resistance, R = `1.125` Ohms.