Question

The center of a circle is at (2, 3) and it has a radius of 3. What is the equation of the circle?

Answer 1

the equation of circle is `x^2+y^2-4x-6y+4=0`

Explanation:

Equation of a circle with radius `r` and center `(h,k)` is given by

`(x-h)^2+(y-k)^2=r^2`

as center in this case is `(2,3)` and `r=3`

the equation of circle is

`(x-2)^2+(y-3)^2=3^2=9` or `x^2-4x+4+y^2-6y+9=9`

or `x^2+y^2-4x-6y+4=0`