How do you simplify #9sqrt2 + sqrt32#?
2 Answers
Feb 13, 2016
I found
Explanation:
We can manipulate the second root and write:
add:
Feb 13, 2016
#13sqrt2 #
Explanation:
to begin , simplify
# sqrt32 # 32 may be written as 16
# xx 2# when simplifying , look for factors which are 'squares' as 16 is.
hence
#sqrt32 = sqrt(16 xx 2 ) = sqrt16 xxsqrt2 = 4sqrt2# expression can now be written :
# 9sqrt2 + 4sqrt2 = 13sqrt2 #