How do you solve #1/(x+3) + 1/(x-3) = 10/ (x^2-9)#?

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Answer 1 · 2016-02-13T23:06:18

#x=5#

#1/(x+3)+1/(x-3)=10/(x^2-9)#

First put everything with same denominator, recalling that #(x+3)(x-3)=x^2-9:#

#(x-3)/(x^2-9)+(x+3)/(x^2-9)=10/(x^2-9)#

We can eliminate the denominators, but keeping in mind that #x!=+-3#

#x-3+x+3=10#

#2x=10#

#x=5#