How do you factor $m^{2} - 2 m$ $m^2 - 2m$ ?

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Answer 1 · 2016-02-14T05:58:42

m(m-2)

If we take m common from ( $m^{2}$ $m^2$ -2m),then only (m-2) remains. It is the shortest form of the binomial ( $m^{2}$ $m^2$ -2m).

How do you factor m2−2mm^2 - 2m?