How do you simplify #(4 + i)(1 – 5i)#?
1 Answer
Feb 14, 2016
9 - 19i
Explanation:
distribute the brackets using FOIL ( or any method you use )
hence
# (4 + i )(1 - 5i ) = 4 - 20 i + i - 5i^2 # [note :
#i^2 = (sqrt-1)^2 = -1 # ]
#so # 4 - 20i + i + 5 = 9 - 19i
