What is the projection of #<-2,3,7 ># onto #<1,6,1 >#?

1 Answer
ali ergin
Feb 15, 2016

#proj_vec B vec A = <23/38,138/38,23/38>#

Explanation:

#vec A= <-2,3,7 >#
#vec B= <1,6,1 >#
#proj_vec B vec A =(vec A * vec B)/|| vec B||^2 * vec B #
#vec A * vec B= -2*1 +3*6 ,7*1 #
#vec A * vec B= -2+18+7=23#
#|| vec B||^2=1^2+6^2+1^2=38#
#proj_vec B vec A =23/38 * <1,6,1 >#
#proj_vec B vec A = <23/38,138/38,23/38>#

Related questions
See all questions in Vector Operations
Impact of this question
1368 views around the world
You can reuse this answer
Creative Commons License