How do you find the volume of the solid obtained by rotating the region bounded by the curves #y^2=4x#, #x=0# and #y=4# about the y axis?
1 Answer
Feb 16, 2016
Explanation:
The graph (before rotation) is shown below
graph{sqrt(4x) [-0.5, 4.5, -0.5, 4.5]}
Slice the solid generated in a manner that is normal to the
Each slice has volume of
#"d"V = pi y^2 "d"x#
#= 4pix "d"x#
The total volume is given by
#int_0^4 4pix "d"x = [2pix^2]_0^4#
#=32pi#
