How much power is produced if a voltage of #2 V# is applied to a circuit with a resistance of #24 Omega#?

1 Answer
Feb 16, 2016

#166.bar6 " mW"#

Explanation:

#P=V*I# (power equals voltage time current)

#I=V/R# (current equals voltage divided by resistance)

#rArr P = V^2/R#

In this case
#color(white)("XXX")P=(2V)^2/(24 Omega)=1/6" W" = 166.bar6 mW#

#color(white)("XXX")#Note on Units used:
#color(white)("XXXXXX")1 " Amp" (A or "Ampere") = (1 V ("volt"))/(1 Omega ("ohm"))#

#color(white)("XXXXXX")1 " Watt" (W) = 1 V ("volt") xx 1 A ("ampere")#

#color(white)("XXXXXX")1000 " mW" ("milliWatts") = 1 " W" ("Watt")#